$q = "SELECT b.email, b.name as uname, b.id as uid FROM xic_groupusers a LEFT JOIN xic_user b ON a.uid = b.id WHERE a.gid = ".$gid;(Zeile 184)
müsste es nicht heißen:
$q = "SELECT b.email, b.name as uname, b.id as uid FROM xic_groupusers a LEFT JOIN xic_user b ON a.uid = b.id WHERE a.gid = .$gid";
oder sö ähnlich?
(die Ausführungszeichen am Ende)
Gruß,
J. Sperling
